Predicted winnerNikola Bartunkova2 – 1Predicted sets · best of 3
Nikola Bartunkova · 53%Win probability47% · Tatjana Maria
Analysis
No recent-form data or head-to-head record was supplied for this second-round meeting, so this preview is built on style and context rather than numbers. Nikola Bartunkova is a young Czech player whose game is built on flat, front-foot baseline hitting, which the quick hard courts and lively night-session conditions in New York tend to reward. Tatjana Maria is one of the most awkward opponents on tour to face: a veteran who slices off both wings, changes height and pace constantly and is happy to make a match ugly and long. That contrast usually produces a scrappy contest in which rhythm disappears, and Maria's experience in best-of-three grinding is a genuine equaliser against a less-established opponent. The edge goes marginally to the bigger, more direct ball-striking on this surface, but only marginally, and a deciding set feels like the most likely shape of the match.
Who is favourite between Nikola Bartunkova and Tatjana Maria?
It is close to a coin toss. We give Bartunkova a slight 53-47 edge because flat, aggressive hitting travels well on the quick New York hard courts, but Maria's variety keeps this genuinely open.
How many sets will Bartunkova vs Maria last?
We predict 2-1, with a roughly 52% chance the match goes to a deciding third set. Contrasting styles and Maria's ability to disrupt rhythm both point towards a long night.
What is the best bet for this match?
Over 2.5 sets, meaning the match goes to three, is the pick at medium risk. With no form data available, straight-winner markets carry more uncertainty than usual.
Head to Head
No head-to-head data was provided for this pairing, so the meeting is treated as a first look for both players. That works both ways: Bartunkova has no prior read on how heavy and low Maria's slice sits on a fast court, while Maria has no template for the pace coming back at her. Matches without history often swing on how quickly one player solves the other's patterns, which is another reason to expect a third set.